Question

two particles are projected simentanously from two towers of height 200 metres distance between two towers is hundred and initial velocity of both the particles is 25 metre per second find what at what distance they particles will collide
who will answer first I will follow them the wrong answers will be reported please answer fast . ​

Answer 1

Answer:

The height of particle A at any instant t is given as,

h

A

=10+u

A

sin45

0

t−

2

1

gt

2

h

A

=10+10

2

sin45

0

t−

2

1

gt

2

=10+10t−

2

1

gt

2

Similarly, height of particle B at any instant t is given as,

h

B

=20−

2

1

gt

2

At the collision, both the heights are equal.

∴ 10+10t−

2

1

gt

2

=20−

2

1

gt

2

⟹t=1s

Explanation:

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Answer 2

Everything available in our environment which can be used to satisfy our needs, is called a resource. It should be technologically accessible, economically feasible and culturally acceptable.