Question

Two particles are projected with same speed

but at angles of projection (45-teeta) and (45+teeta)

. Then their horizontal ranges are

in the ratio of​

Answer 1

ANSWER

Range, R=gu2sin2θ

So,R1=gu2sin(2(45−θ))=gu2cos2θ

R2=gu2sin(2(45+θ))=gu2cos2θ

Hence, R1=R2