Question

Two particles are projected with same speed but at angles of projection (450 - θ) and (450 + θ). Then their horizontal ranges are in the ratio of​

Answer 1

Answer:

1:1

Explanation:

Range, R=gu2sin2θ

So,R1=gu2sin(2(45−θ))=gu2cos2θ

R2=gu2sin(2(45+θ))=gu2cos2θ

Hence, R1=R2

Answer 2

Explanation:

two practices are projects with the same velocity but at angles of projection 45 degree minus theta and 45 degree + theta to have maximum range .

then they are horizontal ranges are in the ratio of

range , r = u^2 sin 2¤ / g

so , r, = u^2 sin 2 (45-¤) /g

= u^2 cos 2¤ / g

r2 = u^2 sin (2(45+¤)) /g

= u^2 cos 2 ¤ /g

hence r1 =r2