Question

Two particles are released from the same height at an interval of 1.0 s. How long
after the first particle begins to fall will the two particle be 10 m apart (g = 10 m/s)​

Answer 1

Answer:after 2second

Step-by-step explanation:

Because it is in five m apart

Answer 2

Step-by-step explanation:

since the particles are release at an interval of 1 sec. so, there will be a difference of 10m/s in there velocities. since the height is same

so by using the formula,

$s = ut + \frac{1}{2} a {t}^{2}$

since they are released so, u=0and s is same, a=g so

$\frac{1}{2} g(t1) ^{2} = \frac{1}{2} g(t2 )^{2}$

so, cancelling the common factors we get

${(t1)}^{2} = {(t2)}^{2}$

since the diffrence between time is 1 sec.

so we get

$2t2 = 1$

we get the difference between time remains 0.5 second.