Question

Two particles are released from the same height at an interval of 1 second. What is the relative acceleration between them.​

Answer 1

Answer:

Two particles are released from same height at an interval of 1 second. How long after the first particle begins to fall will the two particle be 10m apart? (g = 10 m/s2) Solution. Notice that each particle moves zero initial velocity and constant acceleration g = 10 m/s2.

Explanation:

Answer 2

Let the digit in units place be x. 

Then, digit in ten's place =3x

So, original number =10(3x)+x=31x

On interchanging the digits, new number =10x+3x=13x

According to the given condition,

31x+13x=88

⇒44x=88⇒x=2

So, the original number is 31x or 31×2=62.

On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.

So, the resulting number we get is 26.

Here, both answers are correct, as 26+62=88.