Question

two particles are separated at a horizontal distance .they r projected along the same line with different intial speeds [for body A it is u squareroot3,for B it is u].The time after which the horizontal distance b/w them becomes 0 is

[a] x/u [b]x/2u
[c]2u/x [d] none of these

please solve and give the answer

Answer 1

Note:The angle of projections are missing in the given question.LetAngle of projection for A=30oAngle of projection for B=60oRequired condition:Distance traveled by A−Distance traveled by B=x[u3√]cos30o×t−ucos60o×t=x[u3√](3√2)×t−u(12)×t=xut[32−12]=xut=xt=xu
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Answer 2

Heyamate!!

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