Question

Two particles are simultaneously projected in opposite directions horizontally from a given point in space where gravity g is uniform. If u, and u, be their initial speeds, then the time t after which their velocities are mutually perpendicular is given by (1)

Answer 1

Explanation:

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Answer 2

Given :-

Velocity of first particle = ${u}_{1}$

Velocity of Second particle = ${u}_{2}$

Since,

${u}_{1} \perp {u}_{2}$

${u}_{1}•{u}_{2} = 0$

(u1 i - gt j)•(u2 i - gt j) = 0

u1 u2 - g²t² = 0

g²t² = u1u2

t = √(u1u2/g²)

t = √u1u2/g

Answer........