Question

two particles are thrown with same speed from a point on ground in such a way that one attains maximum height h and other maximum range r then 1) R=4h 2)R-h/4 3) R=2h 4)R-h/2

Answer 1

Answer:

First let us write their velocities in vector form, for a particle projected with some velocity v at an angle of θ to the horizontal, the velocity is given as :-

v⃗ =vcosθı^+(vsinθ−gt)ȷ^

⋆ The slope (m) will be :-

⟹m=vsinθ−gtvcosθ

⋆ Now the velocities will be parallel when their respective slopes will be equal. So :-

⟹usin30o−gtucos30o=usin60o−gtucos60o

⟹gt(3–√−1)=u

⟹t=ug(3–√−1)

where,

g = Acceleration due to gravity

t = time