Physics, asked by dharaneesh67, 3 months ago

two particles each of mass M move in a circle of radius r under the action of their mutual gravitational attraction find the speed of each particle

Answers

Answered by ritika123489
3

Answer:

Two particles of equal mass m go around in a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is v. ... v=12√(GmR) D.

Answered by ᏚarcasticᏚoul
4

Answer:

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Two particles of equal mass m go around in a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is v. ... v=12√(GmR) D.

hope this helps you...!!!

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