two particles each of mass M move in a circle of radius r under the action of their mutual gravitational attraction find the speed of each particle
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Two particles of equal mass m go around in a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is v. ... v=12√(GmR) D.
Answered by
4
Answer:
Two particles of equal mass m go around in a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is v. ... v=12√(GmR) D.
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