Physics, asked by umangt, 1 year ago

Two particles executing shm of same frequency meet at x=a/2 while moving in opposite directions. Phase difference between the particles between the particle is

Answers

Answered by priyanshushaw999
51
120° or 2π/3
y =asin©
©=30° and ©=150 ° for particles respectively
so phase difference is 120°

umangt: Hey, your answer is right and approach seens right too, but could you please give a more detailed answer? I'm havibg trouble understanding this
Answered by gadakhsanket
168
Hii dear,

# Answer-
Phase difference = -2π/3

# Explaination-
For particle 1
x1 = a.sin(wt) ...(1)
For particle 2
x2 = a.sin(wt+y) ...(2)

For instance, x1=x2=a/2

From (1)
a/2 = a.sin(wt)
Solving we get,
wt=π/6 or wt=5π/6

Putting these value in (2),
sin(π/6) = a.sin(5π/6+y) = a/2
Solving this,
y=-2π/3

Phase difference between 2 particles is -2π/3. Negative sign indicates particles moving in opposite side.

Hope this is useful...
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