Question

Two particles have equal momenta.What is the ratio of their de-broglie wavelengths?

Answer 1

Hii friend,

Here is your answer....

Given that,

p(momentum) =mv => same .

Then ,

de Broglie's wavelength (lamda) =h/MV

lamda¹ =h¹/p¹

lamda² =h²/p²

(since p¹,p² and h¹,h² are same it cancels each other)

:-lamda¹/lamda² =1/1

:-The ratio will be 1:1.

Hope this helps you a little!!!