Two particles have equal momenta.What is the ratio of their de-broglie wavelengths?
saka82411:
it will be at 1:1 ratio
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Hii friend,
Here is your answer....
Given that,
p(momentum) =mv => same .
Then ,
de Broglie's wavelength (lamda) =h/MV
lamda¹ =h¹/p¹
lamda² =h²/p²
(since p¹,p² and h¹,h² are same it cancels each other)
:-lamda¹/lamda² =1/1
:-The ratio will be 1:1.
Hope this helps you a little!!!
Here is your answer....
Given that,
p(momentum) =mv => same .
Then ,
de Broglie's wavelength (lamda) =h/MV
lamda¹ =h¹/p¹
lamda² =h²/p²
(since p¹,p² and h¹,h² are same it cancels each other)
:-lamda¹/lamda² =1/1
:-The ratio will be 1:1.
Hope this helps you a little!!!
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