Question

two particles having charges Q1 and Q2 when kept at certain distance exert force F on each other if distance is reduced to half force between them becomes : (A)F/2
(B) 2F
(C) 4F
(D) F/4

Answer 1

F=kq1q2/r^2
so if r=>r/2
let the new force be F'
F' = kq1q2/(r/2)^2
F'=4kq1q2/r^2
F'=4F

so force changes to 4F

Answer 2

Hello yaar,

I think the answer to this question is 4F.

hope it helps u.....