Question

two particles having mass m1 and m2 move so that their relative velocity is V and the velocity of their centre of mass is v. then find the total kinetic energy of the system ​

Answer 1

Answer:

Total kinetic energy = KE INITIAL + KE FINAL

Explanation:

INITIAL

$ke = \frac{1}{2}m {v}^{2} \\ = \frac{1}{2} m_{1} {v}^{2} \\ = \frac{ m_{1} {v}^{2} }{2}$

FINAL

$ke = \frac{1}{2}m {v}^{2} \\ = \frac{1}{2} m_{2} {v}^{2} \\ = \frac{ m_{2} {v}^{2} }{2}$

then add

$\frac{ m_{1} {v}^{2} }{2} + \frac{ m_{2} {v}^{2} }{2} \\ \frac{ {v}^{2}(m1 + m2) }{2}$

$ke = \frac{ {v}^{2}(m1 + m2) }{2}$