Question

two particles having masses 1gm and 4gm are moving with equal kinetic energies . The ratio of their linear momenta is ​

Answer 1

KE= 1/2 m*v^2

Momentum (p)=m*v

Set each of the 1 gram and 4 grams KE to 8:

KE=1/2 *1* (4)^2=8

KE=1/2 *4* (2)^2=8

The 1 gram takes 4 m/s to achieve KE of 8.

The 4 gram takes 2 m/s to achieve KE of 8.

Therefore, the ratio of their linear momentum (m*v) is:

1*4/4*2= 4/8= 1/2

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