Question

Two particles held at different heights a and b above the ground are allowed to fall from rest. The ratio of their velocities on reaching the ground is 1) a : b 2) a : b 3) a2 : b2 4) a3 : b3

Answer 1

Answer:

Let we assume that both particles takes time t

1

& respectively to reach the ground.

S=ut+

2

1

at

2

g=10m/s

For first particle, a=5t

1

2

...(1)

For second particle, b=5t

2

2

...(2)

By dividing eq

n

(1)/eq

n

(2)

t

2

t

1

=

b

a

=

b

a

Now applying, V=u+at

10t

1

=V−1 ...(3)

10t

2

=V

2

...(4)

Dividing eq

n

(3)/(4)

V

2

V

1

=

t

2

t

1

=

b

a

V

1

:V

b

=

a

:

b

Answer 2

Answer:

i don't no i am sorry i dont help you sorry