Question

Two particles move along x-axis in the same
direction with uniform velocities 8 m/s and
4 m/s. Initially the first particle is 21m to the
left of the origin and the second one is 7m to
the right of the origin. The two particles meet
from the origin at a distance of
35 m 2) 32 m 3)28 m 4) 56 m
​

Answer 1

Answer:

35m

Explanation:

initial distance between two particles : 7 -(-28) = 28m

v1 = 8m/s

v2= 4m/s

when they meet the difference of the distance travelled by particle 1 and particle 2 will be 28 m

$and \: time \: taken \: will \: also \: be \: same \\ \\( v1 - v2)t \: = 28 \\ (4)t = 28 \\ t = 7 \\ \\ \\ distance \: travelled \: by \: the \: second \: particle \: in \\ 7 \: sec \: is \: 7 \times 4 = 28m \\ i.e \: the \: particles \: will \: meet \: at \: a \: distance \: 28 + 7 = 35m \: from \: the \: origin$