Question

Two particles move M1 and M2 with equal kinetic energy the ratio of magnitude of their Momentum option 1 M1 review M2 option to M2 review M1 and option 3 root a phone receive root M2

Answer 1

If two bodies of masses m1 and m2 have equal kinetic energy, then what is the ratio of their linear momenta?

let Two bodies have masses m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy (v1)= p²/2m1=(m1v1)²/2m2

Let the velocity of 2nd body be = v2

Then its Kinetic energy(v2)= p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

∴(m1v1)/(m2v2) =

Then Ratio = √(2m2) : √(2m1)