Question

Two particles of equal mass go round a circle of radius R
under the action of their mutual gravitational attraction.
The speed of each particle is
​

Answer 1

Given,

Masses of the two particles are m1=m2=m

And radius of the two particles are r1=r2=R

So ,The Gravitational force of attraction between the particles

        $F= \frac{Gm^{2}}{R^{2} }$______(i)

As, centripital force

        $F=\frac{ mV^{2}}{R}$______(ii)

From given condition (1) and (2)

$=>\frac{Gm^{2}}{2R^{2} }=\frac{ mV^{2}}{R}$

$=>V=\frac{Gm}{4R}=\frac{1}{2}\sqrt{\frac{Gm}{R} }$

So the speed of the each particle is   $V=\frac{1}{2}\sqrt{\frac{Gm}{R} }$

 

Answer 2

Explanation:

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