two particles of equal mass M and charge Q are placed at a distance of a 16 centimetre to not experience any force the value of q/m is
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Its because repulsive electrostatic force is balanced by equal and attractive gravitational force
Felec = Fgrav
K q.q /r2 = G m.m/r2
q2 /m2 = G/K
q/m = √G/K = √6.67 x 10-11 / 9 x 109
q/m = √0.74 x 10-20
q/m = 8.6 x 10-11
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Answer:
(G/K)^1/2 is the correct answer.
Explanation:
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