two particles of mass 1.0 kg and 2.0 kg are placed at the separation of 50 cm and the gravitational force between them is
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Answered by
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F=Gm1m2/r2 = 6.67×10^-11×1×2/0.5×0.5 =
2.66×10^-10 N
2.66×10^-10 N
vishnu7440:
answer option is not there
Answered by
7
Answer:
Explanation:Acceleration = (Final velocity - Initial velocity )/ Time
Acceleration = (0 - 50) / 5
Acceleration = -50 / 5
Acceleration = -10m/s^2
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