Two particles of mass 1kg and 0.5 kg are moving in the same direction with speed of 2m/s and 6m/s respectively on a smooth horizontal surface. The speed of centre of mass of the system is
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speed of CM =(m1v1 + m1v1)/(m1 + m2)
= (1×2 + 0.5×6)/(1+0.5) = 5/1.5 = 3.33 m/s
= (1×2 + 0.5×6)/(1+0.5) = 5/1.5 = 3.33 m/s
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