Two particles of mass 200 g each are placed at a separation of 10 cm. Assume that the only forces acting on them are due to their gravitational attraction. Find the acceleration of each when they are allowed to move.
Answers
Answered by
197
Gravitational Force on each particle
F = Gm1m2/r²
F = 6.67 x 10^-11 x 0.2 x 0.2 /(0.1)²
F = 2.67 x 10^-33 N
Acceleration of first particle = acceleration of second particle
a = F / m
a = 2.67 x 10^-33/0.2
a = 1.33 x 10^-32 m/s²
F = Gm1m2/r²
F = 6.67 x 10^-11 x 0.2 x 0.2 /(0.1)²
F = 2.67 x 10^-33 N
Acceleration of first particle = acceleration of second particle
a = F / m
a = 2.67 x 10^-33/0.2
a = 1.33 x 10^-32 m/s²
Answered by
33
Answer:
F = Gm1m2/r^2
=6.67×10^-11×0.2×0.2/(0.1)^2
=0.2668×10^-9
now,
a=f/m
=0.2668×10^-9/0.2
=1.33×10^-9 m/s^2
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