Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.
Answers
Answered by
0
The initial accelerations of two particles 1 kg and 2kg placed 50 cm a part are 5.336×10^-10 m/s²and 2.668×10^-10 m/s²
- Let us go through the given parameters in the question
m1 = 1kg
m2 = 2kg
distance(d) = 50cm
- The GRAVITATIONAL FORCE acting between them F= (Gm1m2)/d²
- Acceleration of particle m1 = F/m1
= Gm2/d²
= 6.67×10^-11×2/0.5²
=5.336×10^-10 m/s²
- Acceleration of particle m2 = F/m1
= Gm2/d²
= 6.67×10^-11×1/0.5²
=2.668×10^-10 m/s²
- The initial accelerations of particles are 5.336×10^-10 m/s² and 2.668×10^-10 m/s²
Similar questions