two particles of masses m and 2m have equal kinetic energies .their de-Broglie wavelengths are in the ratio is...
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Answer:
As we know,
λ=h/mv
λ=
2mE
h
as the kinetic energy of both particles are same so
λ∝
m
1
λ
2
λ
1
=
1
2
Explanation:
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