Question

Two particles of masses m and 2M (M > m) are
connected by a cord that passes over a massless
and frictionless pulley. The tension T in the string
and the acceleration a of the particles is :-
(1) T =2mM/(M-m)g
; a=(M-m/M + m)g
(2) T =4mM/(2M + m)
g; a =(2M-m/2m+M)9
(3) T=(2M-m/2M+m)g
: a=(4mM/M+m)g
(4) T =(2Mm/2M+m)
g; a =(4Mm/2M+m)g

i want frequent answer.​

Answer 1

Answer:

Option 2 is your answer

Explanation:

Where the mass is 2M, system accelerates downwards in that direction So,

Equations will be

T-mg=ma

2Mg-T=2Ma

By adding the equations

We get the value of T

Substitute T to get a

Hope it helps

Answer 2

Explanation:

here is your answer to the question