Two particles of masses m, and m, in projectile
motion have velocities vi and V, respectively
at time t = 0. They collide at time to. Their
velocities become V and V, at time 2t, while
still moving in air. The value of
(m vi + m2 v) -(m, v, + m, v.) is (IIT 2001)
2) (m, + m2)gto
1) zero
3) 2(m, +m)gt,
4)-(m, + m2 dgto
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Explanation:
1 zero id the answer is the correct
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