Question

two particles of masses m1 and m2 have equal kinetic energies the ratio of the magnitude of their momenta is

Answer 1

Final Answer : √m(1)/m(2)


Steps:
1) We know that,
Momentum P = √(2mK)
where m is mass of particle
K is Kinetic Energy of particle.

2) If two particles of mass m(1) and m(2) , then ratio of the magnitude of their momenta.

P(1) = √(2m(1)K)
P(2) = √(2m(2) K)

P(1) /P(2) = √m(1)/m(2)

Answer 2

Hey there!

Given,

Two bodies m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy = p²/2m1=(m1v1)²/2m2

Let the velocity of 2nd body be = v2

Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

 ∴(m1v1)/(m2v2) = $\frac{ \sqrt{2m2} }{ \sqrt{2m1} }$

Then Ratio = √(2m2) : √(2m1)

Hope It Helps You!