Question

two particles osicilate simple harmonically both are at a distance of Y=A/2 crossing each other in opposite direction . calculate the phase difference between them​

Answer 1

Explanation:

Equation of simple harmonic wave is

y=Asin(ωt+ϕ)

Here, y=A2

∴Asin(ωt+ϕ)=A2

So, δ=ωt+ϕ=π6or5π6

So, the phase difference of the two particles when they are

crossing each other at y =A2 in opposite directions are

δ=δ1−δ2

=5π6−π6

=2π3

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