two particles p and q are initially 40 metre apart and p behind q. particle P starts moving with uniform velocity 10 metre per second towards give particle starting from rest has an acceleration of 2 metre per second square in the distance of velocity of 20 m then the minimum distance between P and Q will be
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the moment Q attains the velocity of 10 m/s, the time will correspnd to the minimum distance between the ii
=> v = u + at = 10 = 0 + 2(t)
=> t = 5 s
in 5 s P moves 5x10 = 50 m towards Q & Q moves a further 5x5 = 25 m
therefore min distance = 40 + 25 - 50 = 15 m
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