Question

Two particles P and Q have charges +1.0 μC and –1.0 μC and their separation is 2.0 cm. The dipole moment of system is

0.01 μC m

0.02 μC m

0.03 μC m

μC m

Answer 1

Answer:

diplole moment is given above

Answer 2

Answer:

The dipole moment of the system is 0.02μC-m.

Explanation:

The dipole moment of the system is given as,

$M=qd$      (1)

Where,

M=dipole moment of the system

q=magnitude of charge on the dipole

d=distance between the charges

From the question we have,

The magnitude of the charge of the dipole(q)=1μC

The distance between the charges (d)=2cm=0.02m   (1cm=10⁻²m)

By substituting the values of "q" and "d" in equation (1) we get;

$M=1\mu\times 0.02$

$M=0.02\mu C-m$

Hence, the dipole moment of the system is 0.02μC-m.