Two particles P and Q move towards each other along a straight line MN 51 meters along P starts from M with a velocity 5m/s and a constant acceleration of 1m/s^2 Q starts from N at the same time with velocity 6m/s and a constant acceleration of 3m/s^2. Find the time the particles are 30 meters apart
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Answer:
assuming total time is 2t
for P, at half time
v=X.t,S1=21Xt2
at full time S2=Xt.t+212Xt2=2Xt2
total distance covered by P is S1+S2=2.5Xt2
for particle Q, at half time
v=2Xt,S1=212Xt2=Xt2
at full time S2=2Xt.t+21Xt2=2.5Xt2
total distance covered by Q is S1+S2=3.5Xt2
so distance covered by Q is more then P.
Explanation:
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