Question

Two particles P and Q start their motion from same point along same straight line. P moves with constant velocity 50 m/s and Q starts moving with constant acceleration 10 m/s2. Separation between them after 1 s will be ___ m.

Answer 1

u1 = 50m/s ..velocity of p

u2 = 0m/s ..velocity of Q

t = 1s

s1 = u1 × t = 50 × 1 = 50m

s1 = 50m

a2 = 10m/s²

s2 = ut + 1/2 at²

s2 = 0 + 1/2 10 × 1² = 10/2 = 5m

s2 = 5m

their Separation after 1s = s1 - s2 = 50 - 5 = 45m

Answer 2

Given: P moves with constant velocity 50 m/s and Q starts moving with constant acceleration 10 m/s2

To find: separation between them after 1s

Solution: To find the separation between them after 1sec, we need to find their position after 1 second.

And that will be calculated by using laws of motion

Since particle P is moving with constant velocity, therefore, their position can be calculated as

Sp = u1×t

here Sp will be the distance travelled by particle P in t seconds and u1 will be its constant velocity

so, Sp = 50×1 = 50m

For particle Q, we will find its position through the second law of motion

Sq= ut + 1/2at^2

here Sq will be the distance travelled by Q in 1second, a will be its acceleration

Sq= 0+ 1/2×10×(1)^2

Sq= 5m

The separation between particle P and Q will be Sp - Sq

S = 50-5 = 45m

Therefore, Separation between them after 1 s will be 45m.