Question

Two particles projected simultaneously from point (0, 0) and (1m,0)

with uniform velocity 10 m/s and v m/s respectively, as shown in

the figure. It is found that they collide after time t in space. Then

the value of velocity is​

Answer 1

Answer:

Considering motion in horizontal direction,time taken to collide,

t=

2

10

3

−

2

v

1

t=

10

6

−2v

2

2

...(1)

In vertical direction, 10×

2

1

t−

2

1

gt

2

=

2

v

×t−

2

1

gt

2

5=

2

v

v=5

2

t=

5

6

−10

2

2

2

=1.49 seconds