Question

two particles revolve concentrically in a horizontal plane in the same direction. the time required to complete one revolution for particle A is 3 min , while for particle B is 1 min. the time required for A to complete one revolution relative to B is

Answer 1

Angular speed of a revolving object is given as

$\omega = \frac{2\pi}{T}$

now the angular speed of A is given by

$\omega_a = \frac{2\pi}{3}$

angular speed of B is given by

$\omega_b = \frac{2\pi}{1}$

now the relative angular speed of B with respect to A

$\omega_{ba} = \omega_b - \omega_a$

$\omega_{ba} = \frac{2\pi}{1} - \frac{2\pi}{3}$

so the time to complete one revolution is given as

[\tex]T = \frac{2\pi}{\omega_{ba}}[/tex]

$\frac{1}{T} = 1 - \frac{1}{3}$

$T = 1.5 min$

so it will complete one revolution in 1.5 min

Answer 2

Answer:

so this ur ans

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