Question

Two particles start from the same point at the same time and move along the same straight line. If the distances x and y covered by them in 1 seconds are given by x = t3 – 382 + 6t + 5 213 12 3 2 +2t + 8 when will the particles have the same speed?
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Answer 1

Answer:

Correct option is

B

2a

v

2

A distance between the two particles is maximum when both have the same velocity

let the second move has a velocity v at time t

v=at

t=

a

v

distance cover by the first paticle s

1

is

= s

1

=vt=v×

a

v

=

a

v

2

distance cover the particle s

2

=

2

1

×at

2

=

2a

v

2

distance between both the particle is

s

1

−s

2

=

a

v

2

−

2a

v

2

=

2a

v

2

hence the B option is correc