Two particles with charges q1 and q2 are kept at a certain distance to exert force Fbon each other. If the distance is reduced to one-fifth, then the force between them is
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As per the question two charges are given as
Let the separation distance between them is r.
Hence the Coulombic force of repulsion or attraction between them is -
The distance is reduced to one fifth.Hence, the separation distance between them will be now r/5.
Now the coulombic force between them will be-
Hence, from above we see that the force is increased by 25 times.
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distance is reduced to 25times the previous one...
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