Math, asked by hiyabiloria, 6 months ago

Two partners A and B together lent 44,200 at 10% p.a, compounded annually. The amount A
gets at the end of 3 years is the same as B gets after 5 years. Determine the share of each in the
money lent.​

Answers

Answered by Kaushikm
0

Answer:

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Dear Student,

Please find below the solution to the asked query:

The compound interest formula:A=P(1+rn)ntLet the principal by A be x.Then that by B would be (3903−x).Here n=1, as the interest is compounded annually.The rate of interest, r=4100=0.04The amount received by A after t=7 years,A=P(1+rn)ntA=x⋅(1+0.041)1×7A=x⋅(1.04)7Similarly, the amount received by B after 9 years,A=(3903−x)(1+0.041)1×9A=(3903−x)(1.04)9It is stated that the amounts are equal. Then,x⋅(1.04)7=(3903−x)(1.04)9Dividing thoughout by (1.04)7,x=(3903−x)(1.04)2x=(3903−x)×1.0816x=3903×1.0816−1.0816x2.0816x=4221.4848x=4221.48482.0816=2028Share of A in the original investment=Rs. 2028

Step-by-step explanation:

Answered by kulenurgowdru
1

Answer:

here is ur answers

Step-by-step explanation:

A partner 20000

B partner 24200

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