Math, asked by kesharwanimaas, 1 year ago

Two partners M and N buy a car.M pays his share of 3/7th of the total cost of car.M pays 31540 less than N. what is the cost of car?

Answers

Answered by atharvaganorkar06
4

Answer:


Step-by-step explanation: Let's consider the cost of the car as X. So M pays 3X/7 and hence N pays 4X/7. M pays 31540 less than N.

The equation becomes :-


3X/7 + 31540= 4X/7

31540=X/7

Therefore X=31540×7=220780


That's a cheap car!


Answered by minakshi2082
3

Hi bro,,, how are u?let's see

Answer:


Step-by-step explanation:

Let the share of M be 3x/7.

So, Share of N would be 4x/7.

Because 7x/7 is x.

Now,

According to the problem.....


3x/7 = 4x/7- 31540

= 31540 = 4x/7 - 3x/7

= x/7 = 31540

= x = 31540×7

= x = 220780


So, cost of the car is ₹220,780

just copy it DOWN!!!!!

Similar questions