Two parts of 21 in such a way that ten times
one of them exceed nine times the other by 1
are
Answers
Answered by
14
let us two parts of 21 will be x and y
x+y = 21 ----------1
10x = 9y +1
so, 10x - 9y = 1 ----------2
from Eq 1 and 2
9x+9y = 189
10x-9y = 1
——————
19x = 190
x = 10
now y = 11
hence x = 10 and y = 11
x+y = 21 ----------1
10x = 9y +1
so, 10x - 9y = 1 ----------2
from Eq 1 and 2
9x+9y = 189
10x-9y = 1
——————
19x = 190
x = 10
now y = 11
hence x = 10 and y = 11
Similar questions