Question

Two parts of a number are such that one is half the other. The sum of the two parts is 8 more than their difference. What are the parts and what is the number ?

Answer 1

One is half the other =>  x=y/2
the sum of the two parts = 8 more than their difference
ie  x+y    = 8 + (x - y)
on solving the equation
   x+y -x +y = 8
           2y  = 8  => y = 4
so, x = 4/2 = 2

so , 2 numbers are 2 & 4
Check the solution
I condition =>   x = y/2
                         2 = 4/2
II condition
   x+y = 8 + (x-y)
   2+4  = 8 +(4-2)
       6 = 8 + 2
ie  6(sum of the 2 no.)  = 8  + (more than the difference) 

Answer 2

2 and 4 will be the answer ok