Question

Two passengers are charged for excess of luggage Rs. 34 and Rs. 90 respectively: had the luggage all belonged to one of them, he would have been charged for excess Rs. 174; how much would they have been charged if none had been allowed free?​

Answer 1

Answer:

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Answer 2

Let the free luggage allowed be x kg charge paid for each kg more than x=Rs.y
∴ y(105−2x)=30
105−2x=
y
30
​
−−−−−(i)
y(105−x)=36
105−x=
y
36
​
−−−−−(ii)
Multiplying (i) by 36 and (ii) by 30
630−42x=042x=630
3780−72x=
y
1080
​

3150−30x=
y
1080
​

−+−
​

​

x=
42
630
​
=15
∴ Free luggage allowed =15 kg
From (i) 105−2(15)=
y
30
​

105−30=
y
30
​

y=
75
30
​
=0.4
y=Rs.0.40=40 paise
Let us check (ii)
y(105−x)=30
0.4(105−15)=0.4(90)=36





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