Question

Two paths each 2 m wide run across the middle of a
rectangular field. If the area of cross path is 196 m2 and its
length is 60 m, find its breadth.
(Ans: 40 m) step wise answer for long method​

Answer 1

Answer:

Two paths each 2 m wide run across the middle of a

rectangular field. If the area of cross path is 196 m2 and its

length is 60 m, find its breadth.

(Ans: 40 m) step wise answer for long method

Answer 2

Step-by-step explanation:

Here,

firstly note that, when these two paths cross each other

a square is formed in the middle of side 2m, same as the width of the path.

Area of that square= s²= (2m)²= 4m²

Now while taking the length of these two path

we must subtract the portion the square covers that's= 2m from length and breadth

in the first path

w=2m

length = 60m

after deducting = 60m-2m= 58m

The area of the first path= l×b=2m×58m=116m²

Now on the second path

w= 2m

b= x

after deducting = x-2m

area= 2m(x-2m)

according to the question, the area of these two path

= 196m²

But we know that the area of the square is also included

Therefore,

116m²+2m(x-2m)+4m²= 196m²

120m²+2m(x)-4m²= 196m²

2m(x)= 196m²-116m²

x= 80m²/2m= 40m