Question

two paths of 5m wide running perpendicular for each other in the centre of a rectangular path 80 m long and 70m wide . find the area of the remaining park.​

Answer 1

Answer:

${725m}^{2}$

• step by step instructions: the area of road parallel to length =

$70 m \times 5m = 350m {}^{2}$

• the the area of road parallel to breadth =

$80m \times 5m = 400m {}^{2}$

• the area of common square =

$5m \times 5m = 25m {}^{2}$

Thus, the total area of the road =

$350 m^{2} + 400m {}^{2} - 25m ^{2} = 725 m^{2}$

Answer 2

area of the remaining park. is 4875 m²

Step-by-step explanation:

length of the park = 80 m

breadth of the park = 70 m

area of the path = length × breadth = 80×70 = 5600 m²

length of the path XWUV = 70 m

breadth of the path XWUV = 5 m

area of  the path XWUV =70×5  = 350 m²

length of the path TONM = 80 m

breadth of the path TONM = 5 m

area of the path TONM = 80×5 = 400 m²

area of the common region PQRS = 5×5 = 25 m²

then

area of the path = (area of path XWUV + area of the path TONM )- area of the common region PQRS

= (350 +400 )- 25

= 750 - 25 = 725 m²

area of the remaining  park = area of the park - (area of the path )

= 5600 - 725 m²

= 4875 m²

hence ,

area of the remaining park. is 4875 m²

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