Question

Two paths of distinct width are passing through the centre of a rectangular park wacht they
nerallel to the sides of the park The width of the longer
the shorter paths we 3 m
und 2 m respectively. Find the area of the two paths and area of the remaining part of the park,
rectangular park is 60 m long and 40 m wide​

Answer 1

Answer:

1

Secondary School Math 5 points

A rectangular field is of dimension 20 m x15 m. Two paths run parallel to the sides of

the rectangle through the centre of the field. The width of the longer path is 2 m and

that of the shorter path is 1 m. Find (i) the area of the paths (ii) the area of the

remaining portion of the field (iii) the cost of constructing the roads at the rate of 10

per sq.m

Ask for details Follow Report by Saralkumar1979 04.11.2019

Answers

THE BRAINLIEST ANSWER!

rohityadav1829

rohityadav1829 Expert

rectangle through the centre of the field. The width of the longer path is 1.7 m ...

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Comments Report

bhagyashreechowdhury Ace

The area of the paths is 53 m²

The area of the remaining portion of the field is 247 m².

The cost of constructing the roads at the rate of 10 per sq.m is Rs. 530.

Step-by-step explanation:

Dimensions of rectangular field is 20 m x 15 m

The width of the longer path is 2 m and that of the shorter path is 1 m

Step 1:

The area of the rectangle ABCD = length * breadth = 20 * 15 = 300 m²

Area of the shorter path IJKL = 15 * 1 = 15 m²

Area of the londer path EFGH = 20 * 2 = 40 m^2

and,

Area of the middle common path MNOP = 2 * 1 = 2 m²

∴ Area of the paths is given by,

= [Area of the shorter path IJKL] + [Area of the londer path EFGH] - [Area of the middle common path MNOP]

= 15 + 40 - 2

= 53 m²

Step 2:

∴ Area of the remaining protion is given by,

= [The area of the rectangle ABCD] - [Area of the paths]

= 300 - 53

= 247 m²

Step 3:

The rate of constructing the roads is given as Rs. 10 per sq. meter

∴ The total cost of constructing the roads is given by,

= 53 m² * Rs. 10

= Rs. 530