Physics, asked by banothabhinav2001, 1 year ago

two paticals are moving moving in ccirculaton cicular path os ame radii with angular speed 2rad/s and 4 rad/s the ratio of their centripetal acceleration​

Answers

Answered by Anonymous
35

Answer:

\displaystyle{\dfrac{a_c}{a^{'}_c} =\dfrac{1}{4}}

Explanation:

Given :

Two particles are moving in circular path of same radii .

Let say radius be R .

Angular speed are 2 rad / sec and 4 rad / sec .

We have to find ratio of centripetal acceleration​ .

We know :

Centripetal acceleration​ = Velocity square / Radius .

\displaystyle{a_c=\dfrac{v^2}{R}}

Now their ratio :

\displaystyle{\dfrac{a_c}{a^{'}_c} =\dfrac{\dfrac{2^2}{R}}{\dfrac{4^2}{R}}}}\\\\\\\displaystyle{\dfrac{a_c}{a^{'}_c} =\dfrac{4}{16}}\\\\\\\displaystyle{\dfrac{a_c}{a^{'}_c} =\dfrac{1}{4}}

Hence  ratio of their centripetal acceleration​ is 1 : 4 .

Answered by BrainlyConqueror0901
65

Answer:

{\pink{\green{\sf{\therefore Ratio=1:4}}}}

Explanation:

\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}

• In the given question information given about two particles whose angular speed is given and radius of circular path is same(constant).

• So, we have to find the ratio of their centripetal acceleration.

 \underline \bold{Given : } \\ \bold{For \: First \: particle} \\  \implies Radius = constant = R\\  \implies Angular \: speed ( v_{1} ) = 2  \: rad /s \\  \bold{For \: Second \: particle} \\  \implies Radius = constant = R \\  \implies Angular \: speed( v_{2} ) = 4 \: rad /s  \\  \\  \underline  \bold{To \: Find : } \\  \implies Ratio \: of \: their \:centripetal \:  acceleration = ?

• According to given question :

• We know the formula of centripetal acceleration :

 \bold{By \:Using \: formula} \\  \implies Centripetal \: acceleration( a_{c}) =  \frac{ {v}^{2} }{R}  \\  \\   \bold{Ratio} \\  \implies  \frac{   a_{c1} }{ a_{c2} }  =  \frac{  \frac{ { v_{1} }^{2} }{R}  }{ \frac{ { v_{?} }^{2} }{R} }  \\  \implies \frac{   a_{c1} }{ a_{c2} } =  \frac{ { v_{1} }^{2} }{ v_{2}^{2}  }  \\  \implies \frac{   a_{c1} }{ a_{c2} } =   \frac{ ({2})^{2} \times  \frac{rad}{s}  }{ ({4})^{2} \times  \frac{rad}{s}  }  \\  \implies \frac{   a_{c1} }{ a_{c2} } =  \frac{4}{16}  \\  \implies  \bold{\frac{   a_{c1} }{ a_{c2} } =  \frac{1}{4} } \\  \\   \bold{\therefore Ratio \: of \: centripetal \:  {acc}^{n}  = 1 : 4}

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