two pegs on a wall are 4.5m apart .the distance between them measured parallel to the floor is 3.6m .if one peg is 1.5m above the floor .find th height of the second and its inclination with floor
Answers
Given : two pegs on a wall are 4.5m apart .
the distance between them measured parallel to the floor is 3.6m .
if one peg is 1.5m above the floor .
To find : height of the second and its inclination with floor
Solution:
Horizontal Distance = 3.6 m
Distance = 4.5 m
Vertical Distance = ?
Distance² = (Horizontal Distance)² + (Vertical Distance)²
=> 4.5² = 3.6² + (Vertical Distance)²
=> Vertical Distance = 2.7 m
height of the second from floor = 1.5 + 2.7 = 4.2 m
inclination with floor can not be find until a specific point on floor is mentioned
Assume point just below other peg
Then tanα = 4.2/3.6
=> α = tan⁻¹(7/6) = 49.4°
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