two pen and four erasers cost rs 88which is equal to one pen and thirteen eraser if a man has to purchase 8eraser then how much he has to pay
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Step-by-step explanation:
let,
cost of one pen =X/-
cost of one eraser =Y/-
according to problem
2X + 4Y =88 ------------( i )
1X + 3Y=88
X=88 - 3Y ------------( ii )
subsisting eq( ii ) in eq( i )
so we get
=> 2[ 88 - 3Y ] + 4Y =88
=> 176 - 6Y + 4Y =88
=> 176 - 88 =6Y - 4Y
=> 2Y = 88
=> Y = 88/2
=> Y = 44
therefore cos of one eraser Equal to 44/-
mam has to pay for 8 erasers equal to 352/-
Answered by
1
Hope this helps.............
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