Question

Two pendulum have time period t and 5t 54 they start executing shm at the same time from the mean position what will be the phase difference between them after the bigger pendulum complete one oscillation

Answer 1

✍✍✍Har Har

Here is your answer mate..✌✌✌

Since, bigger pendulum completes one oscillation, it's phase is 2 pi………….(1)

The angular frequency of smaller pendulum is

w=2 pi/T. Therefore , it's phase at time 5T/4 is (according to phase equals to wt)

w 5T/4=( 2 pi/T)(5 T/4)=2.5 pi…………(2)

From (1) and (2) the difference in phase is ( pai/2).