Question

Two pendulums of time periods 3 s and 7 s
respectively start oscillating simultaneously from tu
opposite extreme positions. After how much time
they will be in same phase?​

Answer 1

The time after which the pendulums will be in same phase is t = 21/8 second

Explanation:

y1 =  A sin( ω1t + π/2)

y2 =  A sin( ω2t - π/2)

When in same phase:

( ω1t + π/2) = ( ω2t - π/2)

(ω2 - ω1)t = π

( 2π / 3 - 2π/ 7)t = π

t = 21/8 second

Thus the time after which the pendulums will be in same phase is t = 21/8 second.

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When the length of a simple pendulum is decrease by 20 cm the period changes by 10% find the original length ​?

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