Question

Two people A and B start walking at the same time from their houses towards each other, moving uniformly at speeds of 3 m/s and 5 m/s respectively. If the distance between the houses is 240 meters, find the distance of their meeting point from A’s house.

Answer 1

When speed is constant distance will vary as time

Car A moves for 2 hours @ 25kmph ---------> d = s X t -------> 50 = 25 X 2

Car B moves for 3 hours @ 25kmph ---------> d = s X t --------> 75 = 25 X 3

Here (tA / tB) = (dA / dB) -----> time ratio = distance ratio = 2 : 3

If time of two bodies or motion is constant, then distance will vary as speed

Here (S1 / S2) = (d1 / d2)

If two cars start simultaneously from opposite ends towards each other. They meet at point ‘C’

In this case distance covered by each car will vary as their speeds since they travelled for equal period.

Suppose the distance AB = 900 km Speed A = 25kmph Speed B = 20kmph

In this case their meeting point (C) will be (S1 / S2) = (d1 / d2) ------> 25/20 ----> 5/4 = 500 / 400 i.e. 500 kms from A

Answer 2

Answer:

500 km

Explanation:

Car A moves for 2 hours @ 25kmph ---------> d = s X t -------> 50 = 25 X 2

Car B moves for 3 hours @ 25kmph ---------> d = s X t --------> 75 = 25 X 3

Here (tA / tB) = (dA / dB) -----> time ratio = distance ratio = 2 : 3

If time of two bodies or motion is constant, then distance will vary as speed

Here (S1 / S2) = (d1 / d2)

If two cars start simultaneously from opposite ends towards each other. They meet at point ‘C’

In this case distance covered by each car will vary as their speeds since they travelled for equal period.

Suppose the distance AB = 900 km Speed A = 25kmph Speed B = 20kmph

In this case their meeting point (C) will be (S1 / S2) = (d1 / d2) ------> 25/20 ----> 5/4 = 500 / 400 i.e. 500 kms from A